L1=[0,260]
L2=[0.65,0.7,0.9]
d1={1:120,2:105,3:98,4:96,5:90,6:108,7:150,8:150,9:95,10:90,11:92,12:108}
v=int(input("请输入第3档的起步电量（整数）："))	###每空3分,int
L1.append(v)
sum,fee=0,0
for i in d1.keys():  			###d1.keys()      
    sum+=d1[i]			###d1[i]
print("累计这一年的用电量为：",sum)
if sum>L1[2]:
    fee1=(L1[1]-L1[0])*L2[0]
    fee2=(L1[2]-L1[1])*L2[1]
    fee3=(sum-L1[2])*L2[2]
    fee=fee1+fee2+fee3
elif sum>L1[1]:			###sum>L1[1]
    fee1=(L1[1]-L1[0])*L2[0]
    fee2=(sum-L1[1])*L2[1]
    fee=fee1+fee2
else:
    fee=(sum-L1[0])*L2[0]		###L2[0]
print("用户这一年需交电费为：%.2f元"%fee)