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84 lines
2.3 KiB
84 lines
2.3 KiB
/*
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* trans.c - Matrix transpose B = A^T
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*
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* Each transpose function must have a prototype of the form:
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* void trans(int M, int N, int A[N][M], int B[M][N]);
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*
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* A transpose function is evaluated by counting the number of misses
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* on a 1KB direct mapped cache with a block size of 32 bytes.
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*/
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#include <stdio.h>
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#include "cachelab.h"
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int is_transpose(int M, int N, int A[N][M], int B[M][N]);
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/*
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* transpose_submit - This is the solution transpose function that you
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* will be graded on for Part B of the assignment. Do not change
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* the description string "Transpose submission", as the driver
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* searches for that string to identify the transpose function to
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* be graded.
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*/
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char transpose_submit_desc[] = "Transpose submission";
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void transpose_submit(int M, int N, int A[N][M], int B[M][N])
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{
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}
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/*
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* You can define additional transpose functions below. We've defined
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* a simple one below to help you get started.
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*/
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/*
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* trans - A simple baseline transpose function, not optimized for the cache.
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*/
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char trans_desc[] = "Simple row-wise scan transpose";
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void trans(int M, int N, int A[N][M], int B[M][N])
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{
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int i, j, tmp;
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for (i = 0; i < N; i++) {
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for (j = 0; j < M; j++) {
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tmp = A[i][j];
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B[j][i] = tmp;
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}
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}
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}
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/*
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* registerFunctions - This function registers your transpose
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* functions with the driver. At runtime, the driver will
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* evaluate each of the registered functions and summarize their
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* performance. This is a handy way to experiment with different
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* transpose strategies.
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*/
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void registerFunctions()
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{
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/* Register your solution function */
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registerTransFunction(transpose_submit, transpose_submit_desc);
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/* Register any additional transpose functions */
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registerTransFunction(trans, trans_desc);
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}
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/*
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* is_transpose - This helper function checks if B is the transpose of
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* A. You can check the correctness of your transpose by calling
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* it before returning from the transpose function.
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*/
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int is_transpose(int M, int N, int A[N][M], int B[M][N])
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{
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int i, j;
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for (i = 0; i < N; i++) {
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for (j = 0; j < M; ++j) {
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if (A[i][j] != B[j][i]) {
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return 0;
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}
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}
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}
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return 1;
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}
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