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- /*
- * trans.c - Matrix transpose B = A^T
- *
- * Each transpose function must have a prototype of the form:
- * void trans(int M, int N, int A[N][M], int B[M][N]);
- *
- * A transpose function is evaluated by counting the number of misses
- * on a 1KB direct mapped cache with a block size of 32 bytes.
- */
- #include <stdio.h>
- #include "cachelab.h"
-
- int is_transpose(int M, int N, int A[N][M], int B[M][N]);
-
- /*
- * transpose_submit - This is the solution transpose function that you
- * will be graded on for Part B of the assignment. Do not change
- * the description string "Transpose submission", as the driver
- * searches for that string to identify the transpose function to
- * be graded.
- */
- char transpose_submit_desc[] = "Transpose submission";
- void transpose_submit(int M, int N, int A[N][M], int B[M][N])
- {
- }
-
- /*
- * You can define additional transpose functions below. We've defined
- * a simple one below to help you get started.
- */
-
- /*
- * trans - A simple baseline transpose function, not optimized for the cache.
- */
- char trans_desc[] = "Simple row-wise scan transpose";
- void trans(int M, int N, int A[N][M], int B[M][N])
- {
- int i, j, tmp;
-
- for (i = 0; i < N; i++) {
- for (j = 0; j < M; j++) {
- tmp = A[i][j];
- B[j][i] = tmp;
- }
- }
-
- }
-
- /*
- * registerFunctions - This function registers your transpose
- * functions with the driver. At runtime, the driver will
- * evaluate each of the registered functions and summarize their
- * performance. This is a handy way to experiment with different
- * transpose strategies.
- */
- void registerFunctions()
- {
- /* Register your solution function */
- registerTransFunction(transpose_submit, transpose_submit_desc);
-
- /* Register any additional transpose functions */
- registerTransFunction(trans, trans_desc);
-
- }
-
- /*
- * is_transpose - This helper function checks if B is the transpose of
- * A. You can check the correctness of your transpose by calling
- * it before returning from the transpose function.
- */
- int is_transpose(int M, int N, int A[N][M], int B[M][N])
- {
- int i, j;
-
- for (i = 0; i < N; i++) {
- for (j = 0; j < M; ++j) {
- if (A[i][j] != B[j][i]) {
- return 0;
- }
- }
- }
- return 1;
- }
-
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